WordFind can't count?

[xirisone]

Hi,

I want to detect whether a substring is present in a string.
I try to count how often a substring occurs in a string using WordFind...

As long as the substring occurs at least once it works.
But if the the substring is not present at all I don't get '0' as expected (and needed!) but I get the string I searched in as result.

Any Ideas?

Sample:
${WordFind} "C:\io.sys C:\logo.sys C:\WINDOWS" "sys" "*" $R0
detailprint "found 'sys' [$R0] times." // Ok, result = 2

${WordFind} "C:\io.sys C:\logo.sys C:\WINDOWS" "xyz" "*" $R0
detailprint "found 'xyz' [$R0] times."
This fails, $R0 contains "C:\io.sys C:\logo.sys C:\WINDOWS"

xirisone

[kichik]

As the documentation says, if you don't use E in the options, you get the input string back in case of errors.

If some errors found then (result=input string)

Use the E option and check for the error specifying zero delimiters or just compare the result to the input string.

[xirisone]

@kichik
I'll check that out.

Still I have a problem of understanding... I'd say the result of '0' times found is a valid result and no error. The function should simply return '0'. The documentation even says the code I used is a sample for counting.
xirisone

[kichik]

Where exactly does the documentation say that? I can't find it.

[xirisone]

The documentation at 'E.3.2 WordFind' says:

Example (Sum of delimiters):

Section
${WordFind} "C:\io.sys C:\logo.sys C:\WINDOWS" "sys" "*" $R0
; $R0="2"
SectionEnd

My interpretation was, that I get the count how often the delimiter is found and '0' times found is a valid result (thought it worked without using the E parameter).
The problem itself is easy enough to solve, it's just for my understanding.
TIA,
xirisone