Registered: Aug 2007
From: Frankfurt, Germany

Hello all,

i have a strange problem occuring here, i use the following code to count how many times a String appears in a another String (seperated by ,). But for some reason its counted wrong BCDE are definitely only contained once!

code:

Var /Global LicenseFeatures
Var /Global TESTA
Var /Global TESTB
Var /Global TESTC
Var /Global TESTD
Var /Global TESTE
Var /Global TESTF

Section TEST
	
	StrCpy $LicenseFeatures "A,B,C,D,E,F"
	
   	${WordFind} "$LicenseFeatures" "A" "#" $TESTA					
	${WordFind} "$LicenseFeatures" "B" "#" $TESTB    
   	${WordFind} "$LicenseFeatures" "C" "#" $TESTC		
	${WordFind} "$LicenseFeatures" "D" "#" $TESTD
	${WordFind} "$LicenseFeatures" "E" "#" $TESTE
	${WordFind} "$LicenseFeatures" "F" "#" $TESTF
	
		MessageBox MB_OK "LicenseFeatures: $LicenseFeatures $\r$\n \
						A: $TESTA $\r$\n \
						B: $TESTB $\r$\n \
						C: $TESTC $\r$\n \
						D: $TESTD $\r$\n \
						E: $TESTE $\r$\n \
						F: $TESTF $\r$\n"
SectionEnd

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Registered: May 2009
From:

When you use the "#" as the option for ${WordFind} it returns the sum of the words. What you want is "*" to return the count of delimiters.

code:
Var /Global LicenseFeatures
Var /Global TESTA
Var /Global TESTB
Var /Global TESTC
Var /Global TESTD
Var /Global TESTE
Var /Global TESTF

Section TEST
    
    StrCpy $LicenseFeatures "A,B,C,D,E,F"
    
    ${WordFind} "$LicenseFeatures" "A" "*" $TESTA                   
    ${WordFind} "$LicenseFeatures" "B" "*" $TESTB    
    ${WordFind} "$LicenseFeatures" "C" "*" $TESTC       
    ${WordFind} "$LicenseFeatures" "D" "*" $TESTD
    ${WordFind} "$LicenseFeatures" "E" "*" $TESTE
    ${WordFind} "$LicenseFeatures" "F" "*" $TESTF
    
        MessageBox MB_OK "LicenseFeatures: $LicenseFeatures $\r$\n \
                        A: $TESTA $\r$\n \
                        B: $TESTB $\r$\n \
                        C: $TESTC $\r$\n \
                        D: $TESTD $\r$\n \
                        E: $TESTE $\r$\n \
                        F: $TESTF $\r$\n"
SectionEnd

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Registered: Aug 2007
From: Frankfurt, Germany

Thanks that works, but then what is the sum of the words?

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Registered: May 2009
From:

Sum of words is the count of words parsed between around the delimiter. Since you only have one delimiter in a string it will always show 1 or 2.

Typically you will use it to get the count of items.

Example:

code:
${WordFind} "A,B,C,D,E,F" "," "*" $0
; $0 = 6

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Registered: Aug 2007
From: Frankfurt, Germany

Thanks.

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